This is a real homeopathic remedy: Natrium Muriaticum -table salt- 30 CH, that is, with 30 dillutions of a hundred times each, so that's 10^60 of dillution. It says it's net 30mL.

Assuming this dillution is mass/volume, then there are 10^60 mL of water for every gram of NaCl. For 30 mL of water, that's 3 x 10^-59 g of salt.

In 58,44 g (1 mol) of NaCl there are 6,02 x 10^23 (Avogadro's number) "molecules". Not real molecules because it's a crystal, but you get it; since it's in aqueous solution there's this number of sodium ions and an equal number of chlorine ones.
Therefore in 3 x 10^-59 g there are 3,09 x 10^-37 sodium ions.

But there's no such thing as 3,09 x 10^-37 of an ion or atom or molecule. It's 0, 1, 2, 3, 500 trillion or so on.
Sodium chloride was split in Na+ and Cl- the moment it was dissolved in water, but afterwards its constituent ions remained intact through the whole dillution process.
Maybe I had a wrong supposition or calculation mistake but any conceivable way to model this still shows an absurdly tiny result.

So what can we conclude? There's a very small chance some stray ion found its way into Natrium Muriaticum 30 CH. But it's safe to say there's none of it.
Zero. Nothing.
"Natrium Muriaticum 30 CH" literally is just water without any table salt at all. This is the case for most homeopathic medicines. Some are just concentrated enough to have a handful of molecules of their claimed source, but above 12 C they're arithmethically just water. There is no discussing this.

You can distill this remedy to examine residue. You can run it through any kind of emission or absortion spectroscopy. Any expensive method in analitical chemistry. In any case all that you'll find are trace impurities.
When you buy this you're buying overpriced water.